Respuesta :

Willchemistry
Molar mass CaCl₂ = 110.98 g/mol

number of moles :

n = m / molar mass

n = 330 / 110.98

n =2,9735 moles

Molarity ( M ) = moles solute / liters solution

M = 2.9735 / 1

M = 2.9735 mol/L⁻¹

hope this helps!