[tex]2x^2-5x+3=2x^2-2x-3x+3=2x(x-1)-3(x-1)\\\\=(x-1)(2x-3)[/tex]
If it's equal 0. Then:
[tex](x-1)(2x-3)+0\iff x-1=0\ \vee\ 2x-3=0\\\\x=1\ \vee\ x=1.5[/tex]
