Step 1 Using the Molarity formula and rearranging to solve for moles of solute:
Mol of Solute = Molarity x L of Solution = 2.5 M x .750L = 1.88 mol HNO3
Step 2 Using the moles found in step 1 and the molar mass of HNO3 find the number of grams:
Molar Mass HNO3 = 1.008 + 14.01 + 3(16) = 63.01g
1.88 mol HNO3 ( 63.01g HNO3 / 1 mol HNO3) = 118g HNO3
