Respuesta :

Since

[tex]6^2 = 36,\quad 7^2 = 49[/tex]

Then we have

[tex]6 = \sqrt{36}<\sqrt{45}<\sqrt{49}=7[/tex]

So, the square root of 45 is somewhere between 6 and 7.

Answer:

C

Step-by-step explanation:

Note that

[tex]\sqrt{36}[/tex] < [tex]\sqrt{45}[/tex] < [tex]\sqrt{49}[/tex], that is

6 < [tex]\sqrt{45}[/tex] < 7

The square root lies between 6 and 7 → point C