Respuesta :

apologiabiology
remember
you when you put a negative inside the square root signs, it is complex and undifined

find which values you can use

x+3
what values make it 0? (the boundary between negative and possivie)
x+3=0
x=-3
has to be more than or equal to 0 (because √0=0)
x>-3

2nd one
1-x=0
1-x>0
add x both sides
1>x

so
x>-3 and 1>x
1>x and x>-3
1>x>-3
-3<x<1


B is answer

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