Answer:
yes
Step-by-step explanation:
[tex](3x-1)(3x+1)=9x^{2}-1[/tex] [tex]=\frac{9x^{2} }{9}-\frac{1}{9}=[/tex] [tex]x^{2} -\frac{1}{9}[/tex]
[tex](x-1/3)(x+1/3)=x^{2} -\frac{1}{9}[/tex]
