filletfiliya07 filletfiliya07

03-11-2020
Mathematics

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a man bought a cow and a calf for 990 dollars, paying 8 times as much for the cows as for the calf. what cost of each

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carlos149 carlos149

03-11-2020

Answer:

Let x = the cost of the calf. The cow costs 8 times as much, so it costs 8x. Together they cost $990:

x + 8x = $990

9x=990

x=990/9

x=110

so the calf cost=110

and cow cost =880

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