Answer:
y' = (2x + y cosxy)/(2y + x cosxy)
Step-by-step explanation:
Using implicit differentiation:
y^2 = x^2 + sin xy
2y y' = 2x + cos xy * (xy' + y)
2y y' = 2x + xy' cos xy + y cos xy
2y y' - xy' cosxy = 2x + ycos xy
y' = (2x + y cosxy)/(2y - x cosxy)
