Answer:
∠ BAC ≈ 67.4°
Step-by-step explanation:
Using the sine ratio in the right triangle.
sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{12}{13}[/tex] , then
∠ A = [tex]sin^{-1}[/tex] ([tex]\frac{12}{13}[/tex] ) ≈ 67.4° ( to 1 dec. place )
