abigailbarnes8242 abigailbarnes8242
  • 04-02-2021
  • Mathematics
contestada

Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi

Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=

Respuesta :

Аноним Аноним
  • 04-02-2021

Answer: x = pi

sin²x - 2cos x - 2 = 0

⇔ 1 - cos²x - 2cos x - 2 = 0

⇔ cos²x + 2cos x + 1 = 0

⇔ (cos x + 1)² = 0

⇒ cos x + 1 = 0

⇔ cos x = -1

⇒ x = pi + k2pi

because 0 ≤ x < 2pi

=> x = pi

Step-by-step explanation:

Answer Link

Otras preguntas

Tranny of individual states over the central government: what if states had the power to ignore a federal tax law they did not like ? How could this be a proble
somebody do this plzzz in 5mins plzzzz ill mark u as a brainliest
HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELP
what is arianators??​
What are the two ways to become a natural born citizen? ​
How do the six essential elements of geography contribute to the study of history?
the news related ciber crime​
lily traveled 10 blocks north and 5 blocks east to visit her friend marie. if she were able to walk directly to marie's house, approximately how many blocks wou
he act of a numbers as IT and then som46 one ofone of the number of the othe numer​
A community sports league is raising money by making custom shirts to sell at league games. They plan to sell the shirts for $13. Each shirt cost six dollars to