Answer:
Sum of the first 41 terms = 6724
Step-by-step explanation:
[tex]a_{41} = a_1 + (n - 1 )d = 4 + (41 - 1) \times 8= 4 + 40 \times 8 = 324\\\\S_n = \frac{n}{2}(a_1 + a_n)\\\\s_{41} = \frac{41}{2} (4 + 324) = \frac{41}{2} \times 328 = 41 \times 164 = 6724[/tex]
