The given equation is,
[tex]-3y^2-2y-6=0[/tex]
Here, a = -3, b = -2, c = -6. Therefore, y can be calculated as,
[tex]\begin{gathered} y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}=\frac{2\pm\sqrt[]{4-(4)(-3)(-6)}}{-6}=-\frac{1\pm\sqrt[]{-68}}{3} \\ =\frac{-1+\sqrt[]{68}}{3},\frac{-1-\sqrt[]{68}}{3} \end{gathered}[/tex]
