SOLUTION:
Using the sine rules;
The equations developed;
[tex]\frac{15}{sin102}=\frac{12}{sinJ}[/tex]
Making sinJ the subject;
[tex]\begin{gathered} sinJ=\frac{12sin102}{15} \\ sinJ=0.7825 \\ J=51.49^o \end{gathered}[/tex]
Thus, the angle is 51.5 degrees.
