Answer:
(4) -2
Explanation:
Given the system of equations:
[tex]\begin{gathered} 3x+4y=16 \\ x+y=6 \end{gathered}[/tex]Set x as the subject in the second equation: x=6-y
Substitute x=6-y into the first equation:
[tex]\begin{gathered} 3x+4y=16 \\ 3(6-y)+4y=16 \\ 18-3y+4y=16 \\ y=16-18 \\ y=-2 \end{gathered}[/tex]The value of y that solves the system of equations is -2.
