Answer:
x = ± i
Step-by-step explanation:
given
16x² + 16 = 0 ( subtract 16 from both sides )
16x² = - 16 ( divide both sides by 16 )
x² = - 1 ( take square root of both sides )
[tex]\sqrt{x^2}[/tex] = ± [tex]\sqrt{-1}[/tex] , that is
x = ± i ( the roots are not real )
