Respuesta :

PoeticBlossom
The answer is [tex] 16x^{3} [/tex]
[tex]\bf f(x)=(x^4+9x^2-5)^4\implies \cfrac{dy}{dx}=\stackrel{chain-rule}{4(x^4+9x^2-5)^3(4x^3+18x)}[/tex]